What is the domain of f(x)=|x-3|+1 ?

The domain of f(x)=|x-3|+1 is -infinity <x<infinity

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domain of f(x)=|x-3|+1

domain

f (x) = ∣ x - 3 ∣ + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} + \frac{3 - x}{2}

x^{2} + 2 x - 3

f (x) = \frac{2 x ^{2} - 4}{3 x ^{2} + 6 x - 45}

f (x) = 2 + x^{3} - 2 x^{2} - x + 2

f (x) = \frac{70}{x}

What is the domain of f(x)=|x-3|+1 ?
The domain of f(x)=|x-3|+1 is -infinity <x<infinity