What is the domain of+sqrt(6y-y^2-2) ?

The domain of+sqrt(6y-y^2-2) is -sqrt(7)+3<= y<= sqrt(7)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of+sqrt(6y-y^2-2)

domain

+ 6 y - y^{2} - 2

- 7 + 3 \leq y \leq 7 + 3

Interval Notation

[- 7 + 3, 7 + 3]

Solution steps

Find non-negative values for radicals:

- 7 + 3 \leq y \leq 7 + 3

The function domain

- 7 + 3 \leq y \leq 7 + 3

f (x) = 3 - 2 x + 1

72 - x^{2} + x

2 - 3 X

f (x) = 5 - x + 3 x - 1

f (x) = ln (\frac{1}{x - 6})

What is the domain of+sqrt(6y-y^2-2) ?
The domain of+sqrt(6y-y^2-2) is -sqrt(7)+3<= y<= sqrt(7)+3