What is the domain of f(x)=(x+1)/(x^2+9) ?

The domain of f(x)=(x+1)/(x^2+9) is -infinity <x<infinity

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domain of f(x)=(x+1)/(x^2+9)

domain

f (x) = \frac{x + 1}{x ^{2} + 9}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x ^{2} + 5 x - 14}{( x + 1 ) ( x - 3 ) ( x + 7 )}

\frac{1 0 ^{3 x}}{2}

f (x) = ∣ y - x ∣ = [x]

f (x) = \frac{10}{9 - x ^{2}}

f (x) = \frac{x + 3}{x ^{2} + 9 x + 18}

What is the domain of f(x)=(x+1)/(x^2+9) ?
The domain of f(x)=(x+1)/(x^2+9) is -infinity <x<infinity