What is the domain of (x^2-4x-5)-(x^2+3x+2) ?

The domain of (x^2-4x-5)-(x^2+3x+2) is -infinity <x<infinity

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domain of (x^2-4x-5)-(x^2+3x+2)

domain

(x^{2} - 4 x - 5) - (x^{2} + 3 x + 2)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 12 (x - 8) (x - 6)

f (x) = \frac{x + 3}{\frac{x + 4}{2}}

f (x) = \frac{1}{9 x + 6}

f (x) = \frac{x + 6}{( x - 2 ) ( x + 3 )}

f (x) = \frac{x ^{2} + 2}{x - 7}

What is the domain of (x^2-4x-5)-(x^2+3x+2) ?
The domain of (x^2-4x-5)-(x^2+3x+2) is -infinity <x<infinity