What is the domain of f(x)=\sqrt[4]{x^4-16} ?

The domain of f(x)=\sqrt[4]{x^4-16} is x = 2

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domain of f(x)=\sqrt[4]{x^4-16}

domain

f (x) = 4 x^{4} - 16

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = - \frac{1}{2} x

f (x) = \frac{1}{6 x ^{2} - 18 x - 60}

f (x) = 3 x^{2} - 6 x

f (x) = 36 - x^{2} - x + 2

f (x) = \frac{x - 7}{x - 5}, x < 7

What is the domain of f(x)=\sqrt[4]{x^4-16} ?
The domain of f(x)=\sqrt[4]{x^4-16} is x<=-2\lor x>= 2