What is the domain of f(x)=(sqrt(2+x))/(2-x) ?

The domain of f(x)=(sqrt(2+x))/(2-x) is -2 2

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domain of f(x)=(sqrt(2+x))/(2-x)

domain

f (x) = \frac{2 + x}{2 - x}

- 2 \leq x < 2 or x > 2

Interval Notation

[- 2, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 2 \leq x < 2 or x > 2

\frac{x + 3}{x ^{3} + 27}

f (x) = x + 5 \cdot \frac{9}{x + 4}

\frac{2 - x}{x + 7}

(x + 8) (x + 2)

f (x) = x^{2 - x^{2}}, 0 \leq x \leq 1

What is the domain of f(x)=(sqrt(2+x))/(2-x) ?
The domain of f(x)=(sqrt(2+x))/(2-x) is -2<= x<2\lor x>2