What is the domain of (sqrt(2-x))/(x+7) ?

The domain of (sqrt(2-x))/(x+7) is x<-7\lor-7<x<= 2

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domain of (sqrt(2-x))/(x+7)

domain

\frac{2 - x}{x + 7}

x < - 7 or - 7 < x \leq 2

Interval Notation

(- \infty, - 7) \cup (- 7, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

Find undefined (singularity) points:

x = - 7

Combine real regions and undefined points for final function domain

x < - 7 or - 7 < x \leq 2

(x + 8) (x + 2)

f (x) = x^{2 - x^{2}}, 0 \leq x \leq 1

24 x^{2} - 15253 x + 591064

h (x) = \cdot f (x) = 5 - x \cdot (x^{2} - 1)

f (x) = \frac{1}{x ^{2} + 4 x - 60}

What is the domain of (sqrt(2-x))/(x+7) ?
The domain of (sqrt(2-x))/(x+7) is x<-7\lor-7<x<= 2