What is the domain of f(x)=sqrt(x+5)*9/(x+4) ?

The domain of f(x)=sqrt(x+5)*9/(x+4) is -5 -4

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domain of f(x)=sqrt(x+5)*9/(x+4)

domain

f (x) = x + 5 \cdot \frac{9}{x + 4}

- 5 \leq x < - 4 or x > - 4

Interval Notation

[- 5, - 4) \cup (- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

- 5 \leq x < - 4 or x > - 4

\frac{2 - x}{x + 7}

(x + 8) (x + 2)

f (x) = x^{2 - x^{2}}, 0 \leq x \leq 1

24 x^{2} - 15253 x + 591064

h (x) = \cdot f (x) = 5 - x \cdot (x^{2} - 1)

What is the domain of f(x)=sqrt(x+5)*9/(x+4) ?
The domain of f(x)=sqrt(x+5)*9/(x+4) is -5<= x<-4\lor x>-4