What is the domain of (x^2-9)/(x^2+4x) ?

The domain of (x^2-9)/(x^2+4x) is x 0

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domain of (x^2-9)/(x^2+4x)

domain

\frac{x ^{2} - 9}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

y = \frac{tan ( 3 7 ^{\circ} ) - sin ( 3 0 ^{\circ} )}{csc ( 7 4 ^{\circ} )}

f (x) = \frac{1}{( x - 1 ) ( x - 3 )}

f (x) = h (x) = 9 + x

- x^{2} + 1

What is the domain of (x^2-9)/(x^2+4x) ?
The domain of (x^2-9)/(x^2+4x) is x<-4\lor-4<x<0\lor x>0