What is the domain of f(x)= 1/((x-1)(x-3)) ?

The domain of f(x)= 1/((x-1)(x-3)) is x 3

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domain of f(x)= 1/((x-1)(x-3))

domain

f (x) = \frac{1}{( x - 1 ) ( x - 3 )}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 3

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = h (x) = 9 + x

- x^{2} + 1

f (x, y) = ln (y - 6)

f (x) = \frac{2 x - 2}{- 2 x - x ^{2}}

What is the domain of f(x)= 1/((x-1)(x-3)) ?
The domain of f(x)= 1/((x-1)(x-3)) is x<1\lor 1<x<3\lor x>3