What is the domain of 2/(t^2-2t-3) ?

The domain of 2/(t^2-2t-3) is t 3

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domain of 2/(t^2-2t-3)

domain

\frac{2}{t ^{2} - 2 t - 3}

t < - 1 or - 1 < t < 3 or t > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

t = 3, t = - 1

The function domain

t < - 1 or - 1 < t < 3 or t > 3

f (x) = \frac{2 - x}{x ^{2} - 1}

f (x) = x^{6} + x + 10

f (x) = (\frac{3}{x})^{2}

f (x) = \frac{x - 7}{3}

\frac{6 x ^{2} - 9 x ^{2} + 1}{2 x - 3}

What is the domain of 2/(t^2-2t-3) ?
The domain of 2/(t^2-2t-3) is t<-1\lor-1<t<3\lor t>3