What is the domain of f(x)=(sqrt(x^2-5x-14))/(x-6) ?

The domain of f(x)=(sqrt(x^2-5x-14))/(x-6) is x = 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(x^2-5x-14))/(x-6)

domain

f (x) = \frac{x ^{2} - 5 x - 14}{x - 6}

x \leq - 2 or x \geq 7

Interval Notation

(- \infty, - 2] \cup [7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 7

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

x \leq - 2 or x \geq 7

f (x) = - 3 x - 3 + 3

h (x) = \frac{2}{x + 2}

y = 9 x - 10

f (x) = \frac{x - 6}{- x + 9}

y = \frac{1}{x ( 3 - x ^{2} )}

What is the domain of f(x)=(sqrt(x^2-5x-14))/(x-6) ?
The domain of f(x)=(sqrt(x^2-5x-14))/(x-6) is x<=-2\lor x>= 7