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Popular >

extreme f(x)=2x^2+4x-5

Solution

extreme points

f (x) = 2 x^{2} + 4 x - 5

Solution

Minimum (- 1, - 7)

Solution steps

f^{'} (x) = 4 x + 4

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

2 x^{2} + 4 x - 5 : - 7

Minimum (- 1, - 7)

Graph

Popular Examples

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f (x, y) = 3 x^{2} + y^{2} - x y - 11 x

extreme f(t)=(t)+2u(t)-3e^{-2t}u(t)extreme points

f (t) = (t) + 2 u (t) - 3 e^{- 2 t} u (t)

extreme f(x)=(x-6)e^x extreme points

f (x) = (x - 6) e^{x}

extreme f(x)=(x+14)(x-7)^2 extreme points

f (x) = (x + 14) (x - 7)^{2}

extreme f(x)=x^3-48x,-5<= x<= 5 extreme points

f (x) = x^{3} - 48 x, - 5 \leq x \leq 5

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+4x-5 ?
The extreme f(x)=2x^2+4x-5 is Minimum(-1,-7)