What is the extreme f(x)=0.001x^2+3.8x-70 ?

The extreme f(x)=0.001x^2+3.8x-70 is Minimum(-1900,-3680)

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extreme f(x)=0.001x^2+3.8x-70

extreme points

f (x) = 0.001 x^{2} + 3.8 x - 70

Minimum (- 1900, - 3680)

Solution steps

f^{'} (x) = 0.002 x + 3.8

Find intervals:

Decreasing

: - \infty < x < - 1900,

Increasing

: - 1900 < x < \infty

Plug

x = - 1900

into

0.001 x^{2} + 3.8 x - 70 : - 3680

Minimum (- 1900, - 3680)

f (x) = x^{3} - 27 x + 51

f (x) = x^{3} - 27 x + 50

g (x) = x^{3} - 3 x + 2

f (x) = x^{3} - 3 x + 11

f (x, y) = 144 - 9 x^{2} - 16 y^{2}

What is the extreme f(x)=0.001x^2+3.8x-70 ?
The extreme f(x)=0.001x^2+3.8x-70 is Minimum(-1900,-3680)