What is the extreme f(x)=(log_{10}(x))/x ?

The extreme f(x)=(log_{10}(x))/x is Maximum(e,(log_{10}(e))/e)

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extreme f(x)=(log_{10}(x))/x

extreme points

f (x) = \frac{lo g _{10} ( x )}{x}

Maximum (e, \frac{lo g _{10} ( e )}{e})

Solution steps

f^{'} (x) = \frac{1 - ln ( x )}{ln ( 10 ) x ^{2}}

Find intervals:

Increasing

: 0 < x < e,

Decreasing

: e < x < \infty

Plug

x = e

into

\frac{lo g _{10} ( x )}{x} : \frac{lo g _{10} ( e )}{e}

Maximum (e, \frac{lo g _{10} ( e )}{e})

f (x) = t^{2} - 6 t + 8

P (x, y) = 3 x + 4 y

f (1) = x + 3

f (x) = - \frac{5}{12} x^{3} - 5 x^{2} - 15 x - 6

y = \frac{x ^{3} + 8}{x}

What is the extreme f(x)=(log_{10}(x))/x ?
The extreme f(x)=(log_{10}(x))/x is Maximum(e,(log_{10}(e))/e)