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Popular >

extreme f(x)=t^2-6t+8

Solution

extreme points

f (x) = t^{2} - 6 t + 8

Solution

Minimum (3, - 1)

Solution steps

f^{'} (t) = 2 t - 6

Find intervals:

Decreasing

: - \infty < t < 3,

Increasing

: 3 < t < \infty

Plug

t = 3

into

t^{2} - 6 t + 8 : - 1

Minimum (3, - 1)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=t^2-6t+8 ?
The extreme f(x)=t^2-6t+8 is Minimum(3,-1)