What is the extreme 1/(sqrt(2pi))e^{-(x^2)/2} ?

The extreme 1/(sqrt(2pi))e^{-(x^2)/2} is Maximum(0, 1/(2^{1/2)pi^{1/2}})

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extreme 1/(sqrt(2pi))e^{-(x^2)/2}

extreme points

\frac{1}{2 π} e^{- \frac{x ^{2}}{2}}

Maximum (0, \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}})

Solution steps

f^{'} (x) = - \frac{e ^{- \frac{x ^{2}}{2}} x}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1}{2 π} e^{- \frac{x ^{2}}{2}} : \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

Maximum (0, \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}})

- x^{4} + x^{3} + 2 x^{2} + 11, 0 \leq x \leq 2

f (x) = \frac{1}{3} x^{3} - x^{2} + 4

f (x, y) = e^{15 x y}

f (x) = 9 x^{2} + 3 [- 1.2]

f (x) = - 2 x^{3} - 13

What is the extreme 1/(sqrt(2pi))e^{-(x^2)/2} ?
The extreme 1/(sqrt(2pi))e^{-(x^2)/2} is Maximum(0, 1/(2^{1/2)pi^{1/2}})