What is the extreme f(x)=x+((4))/((x+1)^2) ?

The extreme f(x)=x+((4))/((x+1)^2) is Minimum(1,2)

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extreme f(x)=x+((4))/((x+1)^2)

extreme points

f (x) = x + \frac{( 4 )}{( x + 1 ) ^{2}}

Minimum (1, 2)

Solution steps

f^{'} (x) = 1 - \frac{8}{( x + 1 ) ^{3}}

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x + \frac{4}{( x + 1 ) ^{2}} : 2

Minimum (1, 2)

f (x) = x + 9

f (x) = \frac{x ^{2} + 3 x - 4}{x - 1}

f (x) = \frac{1}{x ^{2} - 16}

f (x) = lo g_{3} (x - 2)

f (x) = \frac{12 x}{x ^{2} + 4}

What is the extreme f(x)=x+((4))/((x+1)^2) ?
The extreme f(x)=x+((4))/((x+1)^2) is Minimum(1,2)