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Popular >

extreme x^2ln(x/8)

Solution

extreme points

x^{2} ln (\frac{x}{8})

Solution

Minimum (\frac{8}{e}, - \frac{32}{e})

Solution steps

f^{'} (x) = 2 x ln (\frac{x}{8}) + x

Find intervals:

Decreasing

: 0 < x < \frac{8}{e},

Increasing

: \frac{8}{e} < x < \infty

Plug

x = \frac{8}{e}

into

x^{2} ln (\frac{x}{8}) : - \frac{32}{e}

Minimum (\frac{8}{e}, - \frac{32}{e})

Popular Examples

range of f(x)=x^2-6x+10 range

f (x) = x^{2} - 6 x + 10

range of f(x)= x/(sqrt(4-x^2))range

f (x) = \frac{x}{4 - x ^{2}}

range of f(x)=(-x^2+6x-8)^{(1/2)}range

f (x) = (- x^{2} + 6 x - 8)^{(\frac{1}{2})}

domain of f(x)=sqrt(x-3)+4 domain

f (x) = x - 3 + 4

domain of f(x)= 1/(x+2)+9 domain

f (x) = \frac{1}{x + 2} + 9

Frequently Asked Questions (FAQ)

What is the extreme x^2ln(x/8) ?
The extreme x^2ln(x/8) is Minimum(8/(sqrt(e)),-(32)/e)