What is the asymptotes of f(x)=((x^3-9x))/(3x^2-6x-9) ?

The asymptotes of f(x)=((x^3-9x))/(3x^2-6x-9) is Vertical: x=-1,Slant: y= 1/3 x+2/3

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asymptotes of f(x)=((x^3-9x))/(3x^2-6x-9)

asymptotes

f (x) = \frac{( x ^{3} - 9 x )}{3 x ^{2} - 6 x - 9}

Vertical : x = - 1, Slant : y = \frac{1}{3} x + \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9} : x = - 1

Horizontal Asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9} :

None

Slant Asymptotes of

\frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9} : y = \frac{1}{3} x + \frac{2}{3}

Vertical : x = - 1, Slant : y = \frac{1}{3} x + \frac{2}{3}

f (x) = \frac{7 x - 8}{9 x + 1}

4 x + 7 y = 8, (4, - 2)

f (x) = \frac{8 - x}{x + 8}

\frac{- 6 x + 12}{5 x - 10}

f (x) = \frac{x + 10}{x ^{2} - 100}

What is the asymptotes of f(x)=((x^3-9x))/(3x^2-6x-9) ?
The asymptotes of f(x)=((x^3-9x))/(3x^2-6x-9) is Vertical: x=-1,Slant: y= 1/3 x+2/3