What is the inverse of f(x)=(x^3-1)^7 ?

The inverse of f(x)=(x^3-1)^7 is cube root of \sqrt[7]{x}+1

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inverse of f(x)=(x^3-1)^7

inverse

f (x) = (x^{3} - 1)^{7}

Solution steps

y = (x^{3} - 1)^{7}

Replace

x

with

y

x = (y^{3} - 1)^{7}

Solve for

y, x = (y^{3} - 1)^{7}

\frac{3 x ^{2} - 13 x + 4}{2 x ^{2} + 7 x - 15}

\frac{8}{( x - 1 ) ( x + 2 )}

\frac{x}{x ^{2} + 4}

y = tan (x)

(8, 10), (- 2, 14)

What is the inverse of f(x)=(x^3-1)^7 ?
The inverse of f(x)=(x^3-1)^7 is cube root of \sqrt[7]{x}+1