en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (-1,6),(2,8)

Solution

distance

(- 1, 6), (2, 8)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 1, 6)

and

(2, 8)

is

= (2 - (- 1))^{2} + (8 - 6)^{2}

Simplify

= 13

Popular Examples

inverse of f(x)=3(x)^2 inverse

f (x) = 3 (x)^{2}

critical f(x)=x^7-7x^5 critical points

f (x) = x^{7} - 7 x^{5}

range of f(x)=sqrt(9-x)range

f (x) = 9 - x

domain of f(x)=sqrt(|x^2-1|)domain

f (x) = ∣ x^{2} - 1 ∣

inverse of f(x)= 1/(11.25x)-1/90 inverse

f (x) = \frac{1}{11.25 x} - \frac{1}{90}

Frequently Asked Questions (FAQ)

What is the distance (-1,6),(2,8) ?
The distance (-1,6),(2,8) is square root of 13