What is the inverse of f(x)=\sqrt[3]{8x}+4 ?

The inverse of f(x)=\sqrt[3]{8x}+4 is (x^3-12x^2+48x-64)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{8x}+4

inverse

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{8}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{8}

f (x) = \frac{( 17 x - 6 )}{( - 9 x - 3 )}

f (x) = \frac{10 e ^{2 x} + 8}{4 + e ^{2 x}}

f (x) = \frac{3 x - 7}{4 x - 7}

f (x) = lo g_{10} (\frac{x + 4}{2}) - 3

What is the inverse of f(x)=\sqrt[3]{8x}+4 ?
The inverse of f(x)=\sqrt[3]{8x}+4 is (x^3-12x^2+48x-64)/8