What is the inverse of f(x)=((3x-1))/((x+2)) ?

The inverse of f(x)=((3x-1))/((x+2)) is (-1-2x)/(x-3)

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inverse of f(x)=((3x-1))/((x+2))

inverse

f (x) = \frac{( 3 x - 1 )}{( x + 2 )}

\frac{- 1 - 2 x}{x - 3}

Solution steps

y = \frac{3 x - 1}{x + 2}

Replace

x

with

y

x = \frac{3 y - 1}{y + 2}

Solve for

y, x = \frac{3 y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 3}

f (x) = \frac{( ( x - 1 ) ^{2} )}{81}

f (x) = (x - 8)^{2} + 1

2^{x + 3} - 5

g (x) = 4 x^{2} - 12

f (x) = \frac{2 - x}{2 + x}

What is the inverse of f(x)=((3x-1))/((x+2)) ?
The inverse of f(x)=((3x-1))/((x+2)) is (-1-2x)/(x-3)