What is the inverse of f(d)=(d+12)/(2d+1) ?

The inverse of f(d)=(d+12)/(2d+1) is (12-d)/(2d-1)

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inverse of f(d)=(d+12)/(2d+1)

inverse

f (d) = \frac{d + 12}{2 d + 1}

\frac{12 - d}{2 d - 1}

Solution steps

y = \frac{d + 12}{2 d + 1}

Replace

d

with

y

d = \frac{y + 12}{2 y + 1}

Solve for

y, d = \frac{y + 12}{2 y + 1}

\frac{12 - d}{2 d - 1}

f (x) = \frac{9 x}{x - 6}

f (x) = \frac{( 17 x - 6 )}{- 9 x - 3}

f (x) = 7 (x^{\frac{1}{5}} + 7)

f (s) = \frac{1}{s ^{3} + a ^{3}}

f (x) = 5 x^{2} + 7

What is the inverse of f(d)=(d+12)/(2d+1) ?
The inverse of f(d)=(d+12)/(2d+1) is (12-d)/(2d-1)