What is the domain of (sqrt(t-2))/(4t-12) ?

The domain of (sqrt(t-2))/(4t-12) is 2 3

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domain of (sqrt(t-2))/(4t-12)

domain

\frac{t - 2}{4 t - 12}

2 \leq t < 3 or t > 3

Interval Notation

[2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 2

Find undefined (singularity) points:

t = 3

Combine real regions and undefined points for final function domain

2 \leq t < 3 or t > 3

f (x) = \frac{5 x + 2}{x - 5}

f (x) = x^{2} - x - 12

y = \frac{2 x + 5}{9 x - 8}

y = \frac{x ^{4} - 16}{x ^{2} - 49}

y = x^{2} - 2

What is the domain of (sqrt(t-2))/(4t-12) ?
The domain of (sqrt(t-2))/(4t-12) is 2<= t<3\lor t>3