What is the domain of \sqrt[3]{1/x-e^x} ?

The domain of \sqrt[3]{1/x-e^x} is x 0

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domain of \sqrt[3]{1/x-e^x}

domain

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{1}{3} arccos (\frac{x}{4} - 2)

f (x) = \frac{x ^{2} - 3 x - 4}{x + 1}

ln (1 - t^{2})

h (x) = \frac{x + 8}{x ^{2} - 64}

f (x) = 1 - ∣ 3 x + 2 ∣

What is the domain of \sqrt[3]{1/x-e^x} ?
The domain of \sqrt[3]{1/x-e^x} is x<0\lor x>0