What is the domain of f(x)=(x^2-3x-4)/(x+1) ?

The domain of f(x)=(x^2-3x-4)/(x+1) is x -1

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domain of f(x)=(x^2-3x-4)/(x+1)

domain

f (x) = \frac{x ^{2} - 3 x - 4}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

ln (1 - t^{2})

h (x) = \frac{x + 8}{x ^{2} - 64}

f (x) = 1 - ∣ 3 x + 2 ∣

f (x) = 3 + 2 x - 1

f (x) = \frac{x}{x ^{2} + 5 x + 6}

What is the domain of f(x)=(x^2-3x-4)/(x+1) ?
The domain of f(x)=(x^2-3x-4)/(x+1) is x<-1\lor x>-1