What is the extreme f(x)=6x^5-160x^3+19 ?

The extreme f(x)=6x^5-160x^3+19 is Maximum(-4,4115),Saddle(0,19),Minimum(4,-4077)

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extreme f(x)=6x^5-160x^3+19

extreme points

f (x) = 6 x^{5} - 160 x^{3} + 19

Maximum (- 4, 4115), Saddle (0, 19), Minimum (4, - 4077)

Solution steps

f^{'} (x) = 30 x^{4} - 480 x^{2}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

6 x^{5} - 160 x^{3} + 19 : 4115

Maximum (- 4, 4115)

Plug

x = 0

into

6 x^{5} - 160 x^{3} + 19 : 19

Saddle (0, 19)

Plug

x = 4

into

6 x^{5} - 160 x^{3} + 19 : - 4077

Minimum (4, - 4077)

Maximum (- 4, 4115), Saddle (0, 19), Minimum (4, - 4077)

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 1

f (x) = \frac{8 x ^{3}}{3} - 5 x^{2} - 3 x + 4

f (x, y) = 6 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

g (x, y) = x^{3} - 3 x y^{2} + y^{3}

f (x) = x^{2} + x

What is the extreme f(x)=6x^5-160x^3+19 ?
The extreme f(x)=6x^5-160x^3+19 is Maximum(-4,4115),Saddle(0,19),Minimum(4,-4077)