What is the extreme f(x)=x^3-12x+11 ?

The extreme f(x)=x^3-12x+11 is Maximum(-2,27),Minimum(2,-5)

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extreme f(x)=x^3-12x+11

extreme points

f (x) = x^{3} - 12 x + 11

Maximum (- 2, 27), Minimum (2, - 5)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 11 : 27

Maximum (- 2, 27)

Plug

x = 2

into

x^{3} - 12 x + 11 : - 5

Minimum (2, - 5)

Maximum (- 2, 27), Minimum (2, - 5)

f (x) = (4 - 2) (4 - 6)^{3} + 8

y = \frac{x ^{2} - 4}{x ^{2} + 4}

f (x) = x^{2} - 12 x + 6

f (x) = x^{2} - 12 x + 7

f (x) = - x^{3} + 3 x^{2} + 5

What is the extreme f(x)=x^3-12x+11 ?
The extreme f(x)=x^3-12x+11 is Maximum(-2,27),Minimum(2,-5)