What is the derivative of xy^2 ?

The derivative of xy^2 is y^2+2xy(dy)/(dx)

What is the first derivative of xy^2 ?

The first derivative of xy^2 is y^2+2xy(dy)/(dx)

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\frac{d}{d x} (x y^{2})

y^{2} + 2 x y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x y^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = y^{2}

= \frac{d x}{d x} y^{2} + \frac{d}{d x} (y^{2}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 1 \cdot y^{2} + 2 y \frac{d y}{d x} x

Simplify

= y^{2} + 2 x y \frac{d y}{d x}

f (x) = x^{3} - x^{2} - x - 10

y = 2 x^{3} + 3 x^{2} - 36 x + 4

f (x, y) = - 2 x^{2} + 5 x y - 3 y^{2} + x + y

f (x) = \frac{5 x - 2}{x ^{2} - 10 x + 25}

p (a, c) = a + 5 + c

What is the derivative of xy^2 ?
The derivative of xy^2 is y^2+2xy(dy)/(dx)
What is the first derivative of xy^2 ?
The first derivative of xy^2 is y^2+2xy(dy)/(dx)