What is the monotone f(x)=sqrt(x-1) ?

The monotone f(x)=sqrt(x-1) is Increasing:1<x<infinity

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monotone f(x)=sqrt(x-1)

monotone intervals

f (x) = x - 1

Increasing : 1 < x < \infty

Solution steps

f^{'} (x) = \frac{1}{2 x - 1}

Find intervals:

Increasing

: 1 < x < \infty

Increasing : 1 < x < \infty

y - 8 x - 7 y = - 6

f (x) = x^{2} + x + 6

9 cos (\frac{1}{3} x + \frac{3}{4})

f (x) = x^{3} - 3 x^{2} + 4

\frac{x}{x ^{2} + 243}

What is the monotone f(x)=sqrt(x-1) ?
The monotone f(x)=sqrt(x-1) is Increasing:1<x<infinity