What is (x+1)^2+y^2=36 ?

The solution to (x+1)^2+y^2=36 is Circle with (a,b)=(-1,0),r=6

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(x+1)^2+y^2=36

(x + 1)^{2} + y^{2} = 36

(a, b) = (- 1, 0), r = 6

Solution steps

(x + 1)^{2} + y^{2} = 36

Rewrite

(x + 1)^{2} + y^{2} = 36

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 6

(x - 1)^{2} + (y - 2)^{2} = 2^{2}

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

(x + 1)^{2} + (y + 4)^{2} = 25

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

x^{2} + y^{2} - 6 x - 4 y + 12 = 0

What is (x+1)^2+y^2=36 ?
The solution to (x+1)^2+y^2=36 is Circle with (a,b)=(-1,0),r=6