What is (x+1)^2+(y+4)^2=25 ?

The solution to (x+1)^2+(y+4)^2=25 is Circle with (a,b)=(-1,-4),r=5

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(x+1)^2+(y+4)^2=25

(x + 1)^{2} + (y + 4)^{2} = 25

(a, b) = (- 1, - 4), r = 5

Solution steps

(x + 1)^{2} + (y + 4)^{2} = 25

Rewrite

(x + 1)^{2} + (y + 4)^{2} = 25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 4), r = 5

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

x^{2} + y^{2} - 6 x - 4 y + 12 = 0

x^{2} + y^{2} - 2 x - 14 y + 25 = 0

x^{2} + y^{2} - 2 x - 3 y = 0

x^{2} + (y - 3)^{2} = 7

What is (x+1)^2+(y+4)^2=25 ?
The solution to (x+1)^2+(y+4)^2=25 is Circle with (a,b)=(-1,-4),r=5