What is 2x^2+2y^2-10x+9y+1=0 ?

The solution to 2x^2+2y^2-10x+9y+1=0 is Circle with (a,b)=(5/2 ,-9/4),r=(sqrt(173))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+2y^2-10x+9y+1=0

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

(a, b) = (\frac{5}{2}, - \frac{9}{4}), r = \frac{173}{4}

Solution steps

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

Rewrite

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- \frac{9}{4}))^{2} = (\frac{173}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - \frac{9}{4}), r = \frac{173}{4}

x^{2} + y^{2} - 6 x - 4 y + 12 = 0

x^{2} + y^{2} - 2 x - 14 y + 25 = 0

x^{2} + y^{2} - 2 x - 3 y = 0

x^{2} + (y - 3)^{2} = 7

(x + 3)^{2} + (y + 2)^{2} = 9

What is 2x^2+2y^2-10x+9y+1=0 ?
The solution to 2x^2+2y^2-10x+9y+1=0 is Circle with (a,b)=(5/2 ,-9/4),r=(sqrt(173))/4