What is x^2+y^2-8x+10y-8=0 ?

The solution to x^2+y^2-8x+10y-8=0 is Circle with (a,b)=(4,-5),r=7

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x^2+y^2-8x+10y-8=0

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

(a, b) = (4, - 5), r = 7

Solution steps

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

Rewrite

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 5))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, - 5), r = 7

(x + 1)^{2} + (y + 4)^{2} = 25

2 x^{2} + 2 y^{2} - 10 x + 9 y + 1 = 0

x^{2} + y^{2} - 6 x - 4 y + 12 = 0

x^{2} + y^{2} - 2 x - 14 y + 25 = 0

x^{2} + y^{2} - 2 x - 3 y = 0

What is x^2+y^2-8x+10y-8=0 ?
The solution to x^2+y^2-8x+10y-8=0 is Circle with (a,b)=(4,-5),r=7