What is x^2+y^2-2x-3y=0 ?

The solution to x^2+y^2-2x-3y=0 is Circle with (a,b)=(1, 3/2),r=(sqrt(13))/2

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x^2+y^2-2x-3y=0

x^{2} + y^{2} - 2 x - 3 y = 0

(a, b) = (1, \frac{3}{2}), r = \frac{13}{2}

Solution steps

x^{2} + y^{2} - 2 x - 3 y = 0

Rewrite

x^{2} + y^{2} - 2 x - 3 y = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - \frac{3}{2})^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, \frac{3}{2}), r = \frac{13}{2}

x^{2} + (y - 3)^{2} = 7

(x + 3)^{2} + (y + 2)^{2} = 9

3 (x - 3)^{2} + 3 y^{2} = 12

x^{2} + y^{2} - 10 y + 16 = 0

x^{2} + y^{2} + 2 x - 2 y = 0

What is x^2+y^2-2x-3y=0 ?
The solution to x^2+y^2-2x-3y=0 is Circle with (a,b)=(1, 3/2),r=(sqrt(13))/2