What is x^2+(y-3)^2=7 ?

The solution to x^2+(y-3)^2=7 is Circle with (a,b)=(0,3),r=sqrt(7)

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x^2+(y-3)^2=7

x^{2} + (y - 3)^{2} = 7

(a, b) = (0, 3), r = 7

Solution steps

x^{2} + (y - 3)^{2} = 7

Rewrite

x^{2} + (y - 3)^{2} = 7

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 7

(x + 3)^{2} + (y + 2)^{2} = 9

3 (x - 3)^{2} + 3 y^{2} = 12

x^{2} + y^{2} - 10 y + 16 = 0

x^{2} + y^{2} + 2 x - 2 y = 0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

What is x^2+(y-3)^2=7 ?
The solution to x^2+(y-3)^2=7 is Circle with (a,b)=(0,3),r=sqrt(7)