What is (x-9)^2+(y+7)^2=169 ?

The solution to (x-9)^2+(y+7)^2=169 is Circle with (a,b)=(9,-7),r=13

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(x-9)^2+(y+7)^2=169

(x - 9)^{2} + (y + 7)^{2} = 169

(a, b) = (9, - 7), r = 13

Solution steps

(x - 9)^{2} + (y + 7)^{2} = 169

Rewrite

(x - 9)^{2} + (y + 7)^{2} = 169

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 7))^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (9, - 7), r = 13

x^{2} + y^{2} \leq 5

3 x^{2} + 4 x + 3 y^{2} - 2 y = 0

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(x + 2)^{2} + (y + 2)^{2} = 25

What is (x-9)^2+(y+7)^2=169 ?
The solution to (x-9)^2+(y+7)^2=169 is Circle with (a,b)=(9,-7),r=13