What is (x-2)^2+(y-1)^2=5^2 ?

The solution to (x-2)^2+(y-1)^2=5^2 is Circle with (a,b)=(2,1),r=5

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(x-2)^2+(y-1)^2=5^2

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

(a, b) = (2, 1), r = 5

Solution steps

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

Rewrite

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 5

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(x + 2)^{2} + (y + 2)^{2} = 25

(x - 5)^{2} + (y - 4)^{2} = 3^{2}

x^{2} + y^{2} + 2 x - 10 y = 0

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

What is (x-2)^2+(y-1)^2=5^2 ?
The solution to (x-2)^2+(y-1)^2=5^2 is Circle with (a,b)=(2,1),r=5