What is ((x+2)^2)/(16)+((y+5)^2)/(16)=1 ?

The solution to ((x+2)^2)/(16)+((y+5)^2)/(16)=1 is Circle with (a,b)=(-2,-5),r=4

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((x+2)^2)/(16)+((y+5)^2)/(16)=1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(a, b) = (- 2, - 5), r = 4

Solution steps

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 4

(x + 2)^{2} + (y + 2)^{2} = 25

(x - 5)^{2} + (y - 4)^{2} = 3^{2}

x^{2} + y^{2} + 2 x - 10 y = 0

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

- x^{2} - 4 x = y^{2} - 20 - 2 y

What is ((x+2)^2)/(16)+((y+5)^2)/(16)=1 ?
The solution to ((x+2)^2)/(16)+((y+5)^2)/(16)=1 is Circle with (a,b)=(-2,-5),r=4