What is (x+2)^2+(y+2)^2=25 ?

The solution to (x+2)^2+(y+2)^2=25 is Circle with (a,b)=(-2,-2),r=5

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(x+2)^2+(y+2)^2=25

(x + 2)^{2} + (y + 2)^{2} = 25

(a, b) = (- 2, - 2), r = 5

Solution steps

(x + 2)^{2} + (y + 2)^{2} = 25

Rewrite

(x + 2)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 2), r = 5

(x - 5)^{2} + (y - 4)^{2} = 3^{2}

x^{2} + y^{2} + 2 x - 10 y = 0

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

- x^{2} - 4 x = y^{2} - 20 - 2 y

3 x^{2} + 3 y^{2} = 12

What is (x+2)^2+(y+2)^2=25 ?
The solution to (x+2)^2+(y+2)^2=25 is Circle with (a,b)=(-2,-2),r=5