What is x^2+y^2+2x-10y=0 ?

The solution to x^2+y^2+2x-10y=0 is Circle with (a,b)=(-1,5),r=sqrt(26)

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x^2+y^2+2x-10y=0

x^{2} + y^{2} + 2 x - 10 y = 0

(a, b) = (- 1, 5), r = 26

Solution steps

x^{2} + y^{2} + 2 x - 10 y = 0

Rewrite

x^{2} + y^{2} + 2 x - 10 y = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 5)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 5), r = 26

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

- x^{2} - 4 x = y^{2} - 20 - 2 y

3 x^{2} + 3 y^{2} = 12

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

(x - 6)^{2} + (y + 3)^{2} = 10

What is x^2+y^2+2x-10y=0 ?
The solution to x^2+y^2+2x-10y=0 is Circle with (a,b)=(-1,5),r=sqrt(26)