What is -x^2-4x=y^2-20-2y ?

The solution to -x^2-4x=y^2-20-2y is Circle with (a,b)=(-2,1),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2-4x=y^2-20-2y

- x^{2} - 4 x = y^{2} - 20 - 2 y

(a, b) = (- 2, 1), r = 5

Solution steps

- x^{2} - 4 x = y^{2} - 20 - 2 y

Rewrite

- x^{2} - 4 x = y^{2} - 20 - 2 y

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 5

3 x^{2} + 3 y^{2} = 12

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

(x - 6)^{2} + (y + 3)^{2} = 10

(x + 4)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

What is -x^2-4x=y^2-20-2y ?
The solution to -x^2-4x=y^2-20-2y is Circle with (a,b)=(-2,1),r=5