What is 3(x-1)^2+3(y-2)^2=12 ?

The solution to 3(x-1)^2+3(y-2)^2=12 is Circle with (a,b)=(1,2),r=2

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3(x-1)^2+3(y-2)^2=12

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

(a, b) = (1, 2), r = 2

Solution steps

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

Rewrite

3 (x - 1)^{2} + 3 (y - 2)^{2} = 12

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 2

- x^{2} - 4 x = y^{2} - 20 - 2 y

3 x^{2} + 3 y^{2} = 12

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

(x - 6)^{2} + (y + 3)^{2} = 10

(x + 4)^{2} + (y - 3)^{2} = 36

What is 3(x-1)^2+3(y-2)^2=12 ?
The solution to 3(x-1)^2+3(y-2)^2=12 is Circle with (a,b)=(1,2),r=2