What is x^2+y^2+6x-8y+24=0 ?

The solution to x^2+y^2+6x-8y+24=0 is Circle with (a,b)=(-3,4),r=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+6x-8y+24=0

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

(a, b) = (- 3, 4), r = 1

Solution steps

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

Rewrite

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 1

(x - 6)^{2} + (y + 3)^{2} = 10

(x + 4)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

8 x^{2} + 8 y^{2} - 32 x + 64 y - 376 = 0

What is x^2+y^2+6x-8y+24=0 ?
The solution to x^2+y^2+6x-8y+24=0 is Circle with (a,b)=(-3,4),r=1