What is (x+4)^2+(y-3)^2=36 ?

The solution to (x+4)^2+(y-3)^2=36 is Circle with (a,b)=(-4,3),r=6

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(x+4)^2+(y-3)^2=36

(x + 4)^{2} + (y - 3)^{2} = 36

(a, b) = (- 4, 3), r = 6

Solution steps

(x + 4)^{2} + (y - 3)^{2} = 36

Rewrite

(x + 4)^{2} + (y - 3)^{2} = 36

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 4, 3), r = 6

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

8 x^{2} + 8 y^{2} - 32 x + 64 y - 376 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y + 1 = 0

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

What is (x+4)^2+(y-3)^2=36 ?
The solution to (x+4)^2+(y-3)^2=36 is Circle with (a,b)=(-4,3),r=6