What is x^2+y^2-5x=0 ?

The solution to x^2+y^2-5x=0 is Circle with (a,b)=(5/2 ,0),r= 5/2

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x^2+y^2-5x=0

x^{2} + y^{2} - 5 x = 0

(a, b) = (\frac{5}{2}, 0), r = \frac{5}{2}

Solution steps

x^{2} + y^{2} - 5 x = 0

Rewrite

x^{2} + y^{2} - 5 x = 0

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, 0), r = \frac{5}{2}

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(x - 20)^{2} + (y - 0.05)^{2} = 81

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

(x - 3)^{2} + (y + 4)^{2} = 2

What is x^2+y^2-5x=0 ?
The solution to x^2+y^2-5x=0 is Circle with (a,b)=(5/2 ,0),r= 5/2