What is 2x^2+2y^2-2x-6y-13=0 ?

The solution to 2x^2+2y^2-2x-6y-13=0 is Circle with (a,b)=(1/2 , 3/2),r=3

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2x^2+2y^2-2x-6y-13=0

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

(a, b) = (\frac{1}{2}, \frac{3}{2}), r = 3

Solution steps

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

Rewrite

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{3}{2}), r = 3

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(x - 20)^{2} + (y - 0.05)^{2} = 81

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

(x - 3)^{2} + (y + 4)^{2} = 2

(x - 9)^{2} + (y + 1)^{2} = 36

What is 2x^2+2y^2-2x-6y-13=0 ?
The solution to 2x^2+2y^2-2x-6y-13=0 is Circle with (a,b)=(1/2 , 3/2),r=3