What is ((x-5)^2+y^2)/(25)=1 ?

The solution to ((x-5)^2+y^2)/(25)=1 is Circle with (a,b)=(5,0),r=5

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((x-5)^2+y^2)/(25)=1

\frac{( x - 5 ) ^{2} + y ^{2}}{25} = 1

(a, b) = (5, 0), r = 5

Solution steps

\frac{( x - 5 ) ^{2} + y ^{2}}{25} = 1

Rewrite

\frac{( x - 5 ) ^{2} + y ^{2}}{25} = 1

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 5

(x - 4)^{2} + y^{2} - 4 = 0

x^{2} + y^{2} + 4 x - 6 y + 3 = 0

(x - 13.4)^{2} + (y + 2.6)^{2} = 100

(x - 3)^{2} + (y + 5)^{2} = 36

x^{2} + y^{2} + 18 x + 4 y - 15 = 0

What is ((x-5)^2+y^2)/(25)=1 ?
The solution to ((x-5)^2+y^2)/(25)=1 is Circle with (a,b)=(5,0),r=5